For reaction `A+2BtoC`. The amount of C formed by starting the reaction with 5 mole of A and 8 mole of B is :

Options

A. 5 moles
B. 8 moles
C. 16 moles
D. 4 moles

Answer

D

Explanation

`A+2BrarrC`
1 mole of A reacts with 2 moles of B
`therefore" 5 moles of A will react with 10 moles of B."`
But we have only 8 moles of B.
Hence, B is the limiting reactant
2 moles of B form 1 mole of C
`therefore" 8 mole of B will form C = 4 moles."`