A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.

Options

A. `2E(y//x)`
B. `xy//E`
C. `E//y`
D. `y//E`

Answer

A

Explanation

If m is the atomic mass of the metal M, then 16 y g of oxygen combine with x m g of the metal.
`therefore" 8 g of oxygen will combine with metal"`
`=(xm)/(16y)xx8=(xm)/(2y)`
` therefore (xm)/(2y)=E" or "m=2E(y//x)`