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0.32 g of metal gave on treatment with a...

0.32 g of metal gave on treatment with an acid 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal

A

58

B

32

C

11.2

D

24

Text Solution

Verified by Experts

The correct Answer is:
B
Equivalent weight of a metal is the mass of the metal which produces 11200 mL of `H_(2)` at NTP.
112 ml of `H_(2)` at NTP are produced from metal
`=0.32 g`
`therefore 11200` mL of `H_(2)` will be produced from metal
`=(0.32)/(112)xx11200`
= 32 g
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