Sucross solution which is `40%` by mass is heated till it becomes `50%` by mass. Water lost form 100 g of the solution is

Options

A. 10 g
B. 15 g
C. 20 g
D. 25 g

Explanation

To solve the problem of how much water is lost when heating a sucrose solution from 40% by mass to 50% by mass, we can follow these steps:

### Step 1: Determine the initial composition of the solution
Given that the sucrose solution is 40% by mass, this means:
- Mass of sucrose = 40% of 100 g = 40 g
- Mass of water = 100 g - 40 g = 60 g

### Step 2: Understand the final composition of the solution
When the solution is heated and becomes 50% by mass sucrose, this means:
- Mass of sucrose remains the same = 40 g
- Mass of water must also be equal to the mass of sucrose to maintain the 50% by mass ratio.

### Step 3: Calculate the required mass of water for the final solution
Since the final solution is 50% sucrose, the mass of water must also be 40 g (to maintain the 50% ratio):
- Mass of water = 40 g

### Step 4: Calculate the loss of water
Now, we can find out how much water has been lost during the heating process:
- Initial mass of water = 60 g
- Final mass of water = 40 g
- Water lost = Initial mass of water - Final mass of water = 60 g - 40 g = 20 g

### Conclusion
The amount of water lost from 100 g of the sucrose solution when heated from 40% to 50% by mass is **20 g**.

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