Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.
`NaClO_(4), NaClO_(3), NaClO, KClO_(2), Cl_(2)O_(7), ClO_(3), Cl_(2)O, NaCl, Cl_(2), ClO_(2)`.
Which oxidation state is not present in any of the above compounds?`

Explanation

Let the O.N of CI in these compound be x
O.N of CI in `NaCIO_(4) therefore +1+x+4(-2)=0 or x=+7` ltvbrgt O.N of CI in `NaCIO_(3) therefore +1 +x+3(-2)=0 or x=+5`
O.N of cI in `NaCIO therefore +1 +x+1 (-2)=0 or x=+1`
O.N of CI in `NaCIO_(2) therefore +1+x+2(-2)=0 or x=+3`
P.N of CI in `CIO_(3) therefore x+3(-2)=0 or x=+6`
O.N of CI in `CI_(2)O therefore 2x+1(-2)=0 or x=+1`
O.N of CI in `CI_(2) therefore 2x=0 or x=0`
O.N of CIin `CIO_(2) therefore 2x=0 or x=0`
O.N of CI in `CIO_(2) therefore x+2 (-2)=0 or x=+4`
None of the compounds have an O.N of +2
increasing order of O.N of CI is : -1,0,+1,+3,+4,+5,+6+7