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Prove that measure of each angle of an...

Prove that measure of each angle of an equilateral triangle is `60^0dot`

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Given: `ΔABC` is an equilateral triangle.
To prove: `∠A=∠B=∠C=60^@`
Proof: In `ΔABC`,
`AB=BC=CA`
Since angles opposite to equal sides of a triangle are equal.
`AB=BC` and `BC=CA`
`=>∠C=∠A and ∠A=∠B`
`=>∠A=∠B=∠C`
Now,
In `ΔABC`,
`∠A+∠B+∠C=180^@`
`=>∠A+∠A+∠A=180^@`
`=>3∠A=180^@`
`∠A=180^@/3`
`=>∠A=60^@`
`therefore ∠A=∠B=∠C=60^@`
Hence proved.
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