In a right angled triangle, one acute angle is double the other. Prove that the hypotenuse is double the smallest side.

Explanation

To prove that in a right-angled triangle, where one acute angle is double the other, the hypotenuse is double the smallest side, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Angles**:
Let the acute angles of the triangle be \( A \) and \( C \). According to the problem, let angle \( A = x \) and angle \( C = 2x \). Since triangle \( ABC \) is a right triangle, angle \( B = 90^\circ \).

2. **Use the Angle Sum Property**:
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