In a ` A B C ,` it is given that `A B=A C` and the bisectors of `/_B\ a n d\ C` intersect at `Odot` If `M` is a point on `B O` produced, prove that `/_M O C=\ /_A B C`

Explanation

To solve the problem, we need to prove that the angle \( \angle MOC = \angle ABC \) given the conditions of the triangle \( ABC \) and the point \( M \) on the extended line \( BO \).

### Step-by-Step Solution:

1. **Identify the Given Information:**
- We have triangle \( ABC \) where \( AB = AC \). This means triangle \( ABC \) is isosceles with \( AB \) and \( AC \) being the equal sides.
- The angle bisectors of \( \angle B \) and \( \angle C \) intersect at point \( O \).
- Point \( M \) is on the line \( BO \) extended.
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