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Prove that each angle of an equilatera...

Prove that each angle of an equilateral triangle is `60^0`

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Let `/_\ ABC, be an equilateral triangle.`
Then, `AB=BC=CA`
Since angles opposite to equal sides of a triangle are equal.
`AB=BC and BC=CA`
`=>/_C=/_A and /_A=/_B`
=>`/_A=/_B=/_C`
But,`/_A+/_B+/_C=180^@`
Therefore,`3/_A=180^@`
`/_A=60^@`
Hence,`/_A=/_B=/_C=60^@`
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