In Figure, `P Q=P Rdot` Show that `P S > P Q`

In Figure, A P _|_l a n d P R > P Q . Show that A R > A Q Given: A P_|_l a n d P R > P Q To Prove: A R > A Q Construction: Mark a point S on P R such that P S=P Qdot Join A S

In Figure, P Q R S and A B R S are parallelograms and X is any point on side B Rdot Show that : a r(^(gm)P Q R S)=a r(^(gm)A B R S) a r(A X S)=1/2a r( P Q R S)

In Figure, P S D A is a parallelogram in which P Q=Q R=R S\ a n d\ A P B Q C Rdot Prove that a r\ (\ P Q E)=\ a r\ (\ C F D)dot

In Fig. 4.90, if P S Q R , prove that P O S ~ R O Q . (FIGURE)

In Figure, P Q R S is a quadrilateral. P Q is its longest side and R S is its shortest side. Prove that /_R > /_P a n d /_S > /_Q Given : P Q R S is a quadrilateral. P Q is its longest side and R S is its shortest side. To Prove : (i) /_R > /_P (ii) /_S > /_Q Construction : Joint P R a n d Q S

In A B C and P Q R Figure, A B=P Q ,B C=Q R and C B and R Q are extended to X and Y respectively and /_A B X =/_P Q Ydot Prove that A B C~=P Q Rdot Figure

In Figure, P Q R is a triangle and S is any point in its interior, show that S Q+S R

In Fig 7.51, P R\ >\ P Q and PS bisects /_Q P R . Prove that /_P S R\ >/_P S Q .

In Fig. 6.15, /_P Q R=/_P R Q , then prove that /_P Q S=/_P R T .

Let p,q,r be the statements p: X is a rectangle, q: x is a square, r:p to q Show that p to r is not a tautology.