In ` P Q R` , `S` is any point on the side `Q R` . Show that `P Q+Q R+R P >2P S`

Explanation

To prove that \( PQ + QR + RP > 2PS \) for triangle \( PQR \) with point \( S \) on side \( QR \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Triangle and Points**:
Let's consider triangle \( PQR \) with points \( P \), \( Q \), \( R \), and point \( S \) located on side \( QR \).

2. **Apply the Triangle Inequality**:
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