`C D E` is an equilateral triangle formed on a side `C D` of a square `A B C Ddot` Show that ` A D E\ ~= B C Edot`

Explanation

To show that triangle \( ADE \) is congruent to triangle \( BCE \), we will use the SAS (Side-Angle-Side) congruence criterion. Here’s a step-by-step solution:

### Step 1: Identify the Given Information
We have a square \( ABCD \) and an equilateral triangle \( CDE \) formed on side \( CD \).

### Step 2: Analyze the Angles
Since \( CDE \) is an equilateral triangle, all its angles are \( 60^\circ \). Therefore:
- \( \angle DCE = 60^\circ \)
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