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If P Q R\ ~= E F D , then E D= PQ (b) ...

If ` P Q R\ ~= E F D ,` then `E D=` PQ (b) QR (c) PR (d) None of these

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Given : ` triangle PQR ~= triangle EFD `
Solution : As we know that corresponding part of congruent triangle ED of `triangleEFD` is equal to the PR of `trianglePQR`
`therefore` option (a) is correct.
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