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The lengths of the sides of a triangl...

The lengths of the sides of a triangle are `5\ c m ,\ 12\ c m\ a n d\ 13 c mdot` Find the length of perpendicular from the opposite vertex to the side whose length is `13\ c mdot`

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Area Of Triangle = Square Root Of (S(S-A)(S-B) (S-C))
Now S = `5+12+13/2 = 15`
Now Simply, Area = `Square Root of (15×10×3×2)`
Area = Square Root Of `(900)`
Area = `30`
Now Area Of Triangle = `1/2 `xx Base Height`
Now Base = `13`
Now, `1/2×13xx Height `= `30`
`13` ×Height =` 60`
Height = `60/13 = 4.61 cm`.
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