A field is in the shape of a trapezium whose parallel sides are 25m and 10 m. The non-parallel sides are 14m and 13m. Find the area of the field.
Let ABCD be a trapezium with,`AB∥CD`

Explanation

`AB=25m,CD=10m BC=14m AD=13m`
Draw CE∥DA. So, ADCE is a parallelogram with,
`CD=AE=10m`
`CE=AD=13m`
`BE=AB−AE=25−10=15m`
In`/_\BCE, the semi perimeter will be,s=
1/2(a+b+c)`
`s=(14+13+15)/2=21m`​
Area of `/_\BCE,A=sqrt(s(s−a)(s−b)(s−c))`
`=sqrt(21(21−14)(21−13)(21−15))`
`=sqrt(21xx7xx(8xx6)`
`=sqrt(7056)=84m^2`
Also, area of `/_\BCE is,A=1/2xxbasexxheight`
`84=1/2xx15xxCL`
`(84×x2)/15=CL`
`CL=56/5m`
Now, the area of trapezium is,`A=1/2`(sum of parallelsides)(height)
`A=1/2xx(25+10)xx(56/5)`
`A=196m^2`

Therefore, the area of the trapezium is `196m^2`