The adjacent sides of a parallelogram `ABCD` measures `34 cm` and `20 cm` and the diagonal `AC=42 cm` Then find its area

Explanation

`AD =20cm`
`CD =34 cm`
`AC = 42 cm`
in `/_\ ADC,s= 34+20+42 = 48`
As per Heron's formula area of triangle`=sqrt(s(s−a)(s−b)(s−c))`
Area of`/_\ ADC =sqrt(48(48−34)(48−20)(48−42))`
Area of `/_\ ADC =sqrt(48xx14xx28xx6))`
Area of `/_\ADC =336 cm^2`
Area of parallelogram `=2xxarea of/_\ ADC`
`= 672 cm^2`