The sides of a triangle are `16 c m ,\ 30 c m\ a n d\ 34 c mdot` Its area is
`225\ c m^2` (b) `240\ c m^2` `225\ sqrt(2\ )\ c m^2` (d) `450\ c m^2`

Explanation

"Let the sides of the triangles be `a=16cm, b=30cm and c=34cm`

semiperimeter of the triangle, `s=(a+b+c)/2`

`s=(16+30+34)/2`

`s=40`

Now, area of triangle by using heron's formula = `(ssqrt((s-a)(s-b)(s-c)))`

`(40sqrt((40-16)(40-30)(40-34)))`

`240 cm^2`

Hence, option (b) is correct."