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The sides of a triangle are 11 c m ,\ ...

The sides of a triangle are `11 c m ,\ 15 c m\ a n d\ 16 c mdot\ ` The altitude to the largest side is
`30\ sqrt(7)\ c m` (b) `(15sqrt(7))/2\ c m` (c) `(15\ sqrt(7))/4c m\ ` (d) `30\ c m`

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Let the sides of the triangles be `a=11cm, b=15cm and c=16cm`
semiperimeter of the triangle,`s=(a+b+c)/2`
`s=(11+15+16)/2`
Now, area of triangle by using heron's formula = `(ssqrt((s-a)(s-b)(s-c)))`
`(21sqrt((21-11)(21-15)(21-16)))`
`30sqrt7 cm^2`
`therefore` area of triangle = `1/2xxbasexxheight`
`30sqrt7=1/2xx16xx`altitude
...
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