Two chords `A B\ a n d\ C D` of a circle are parallel and a line `l` is the perpendicular bisector of `A Bdot` Show that `l` bisects `C D`

Explanation

To prove that the line \( l \), which is the perpendicular bisector of chord \( AB \), also bisects the parallel chord \( CD \), we can follow these steps:

### Step-by-Step Solution

1. **Understanding the Setup**:
- Let \( O \) be the center of the circle.
- Chords \( AB \) and \( CD \) are parallel.
- Line \( l \) is the perpendicular bisector of chord \( AB \).
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