Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the distance between AB and CD is 6 cm, find the radius of the circle.

Explanation

Given: `AB=5cm` and `CD=11cm`

Distance between AB and CD is `6cm`

OL and OM are the perpendiculars on CD and
AB respectively which bisect
CD and AB.

Let `OL=x`, then `OM=x+6`

In right `triangleOLD`

`OD^2=OL^2+LD^2`

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