The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of the other chord from the centre?

Explanation

Given : Two parallel chords of a circle are 6cm and 8cm and distance of smaller chord is 4cm.

Solution :As we know that the perpendicular line from center to chord divides chord into two equal parts.

Now, radius of the circle is `sqrt(3^2+4^2)=5`.

Since, the radius is `5`cm.

So, therefore the distance from center to largest chord is `sqrt(5^2-4^2)=3`.