If two chords of a circle are equally inclined to the diameter through their point of intersection, prove that the chords are equal.

Explanation

Given: Two chords of a circle are equally inclined to the diameter.

To prove: Chords are equal i.e AB=AC

Cons. : Draw `OLbotAB` and `OMbotAC`

Proof: In `triangleOLA` and `triangleOMA`

`angleOLA=angleOMA=90^*`

`OA=OA` (common)

`angleOAL=angleOAM`

`triangleOLA~=triangleOMA` (By RHS)

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