`L\ a n d\ M` are mid-point of two equal chords `A B\ a n d\ C D` of a circle with centre `O` . Prove that `/_O L M=\ /_O M L` (ii) `/_A L M=\ /_C M L`

Explanation

Here, given : AB and CD are two equal chords of a circle with center O.L is the mid-point of AB and M is the mid-point of CD.

`therefore` L is the mid-point of chord AB of circle with center O.

`OLbotAB`

Similarly, `OMbotCD`

Now, chord AB=chord CD

`OL=OM` (Equal chords are equidistant from the center)

In `triangleOLM`

`OL=OM`

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