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Two circles are drawn with sides `A B ,A C` of a triangle `A B C` as diameters. The circles intersect at a point `Ddot` Prove that `D` lies on `B Cdot`

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Cons. : Join AD. As, we know that angle in a semi-circle is a right angle.
`therefore` `angleADB=90^@` and `angleADC=90^@`
`angleADB+angleADC=90^@+90^@ `=`180^@`
So, BDC is a straight line.
Hence, D lies on BC.
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RD SHARMA-CIRCLE -All Questions
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