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A B C and A D C are two right triangles ...

`A B C` and `A D C` are two right triangles with common hypotenuse `A Cdot` Prove that `/_C A D=/_C B Ddot`

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Proof: Since `angleABC` and `angleADC` are `90^@`.
These angles are in the semi-circle
Thus, both the triangles are lying in the semi-circle and AC is the diameter of the circle.
Points A,B,C and D are concyclic.
Hence, CD is the chord.
`angleCAD=angleCBD` (Angles in the same segment of the circle)
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