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Two diameters of a circle intersect each...

Two diameters of a circle intersect each other at right angles. Prove that the quadrilateral formed by joining their end-points is a square.

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Solution
Let assume `AB` and `CD` be the diagonals of a circle such that `AB_|_CD`
Now,
Construction
Joining points `A,B,C,D` in order
we see that
`AB` and `CD` are the equal diagonals of quad.`ACBD` which intersect at right angle.
Hence proved `ACBD` is a square.
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