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A B C and A D C are two right triangles ...

`A B C` and `A D C` are two right triangles with common hypotenuse `A Cdot` Prove that `/_C A D=/_C B Ddot`

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Solution:
`/_ABC=/_ADC`
`/_\ABC` and `/_\ADC` lie on the same semi circle and on a common diameter `AC`
`A,B,C,` and `D` are concyclic
`CD` is a chord
`:. /_CAD =/_CBD`(The angle made by a chord on the same segment are equal)
Hence Proved.
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