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A B C D is a cyclic quadrilateral. A Ba ...

`A B C D` is a cyclic quadrilateral. `A Ba n dD C` are produced to meet in `Edot` Prove that `E B CcongE D A dot`

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Solution:
Given
`ABCD` is a cyclic quadilateral and `AB` and `DC` are produced to meet at `E`
proof:
In `/_\ EBC and /_\EDA`
`/_EBC=/_EDA`(enterior angle in a cyclic quadilateral is equal to the opposite interial angle)
`/_E=/_E`(comman)
`/_ECB=/_EDA`(exterial angle in a cyclic quadilateral is equal to the opposite of interial angle)
`:. /_\EBC~=/_\EDA`(by AAA rule).
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