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P Q\ a n d\ R S are two parallel chord...

`P Q\ a n d\ R S` are two parallel chords of a circle and lines `R P\ a n d\ S Q` intersect each other at `O` as shown in Figure. Prove that `O P=O Q`

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In cyclic quadrilateral
`PQRS`:
`PQ|\|RS`
`=>PR=QS`
We know from the properties of circle,
`OP⋅OR=Hoq⋅OS`
Above can also be written as
`OP⋅(OP+PR)=OQ⋅(OQ+QS)`
`=>OP^2−OQ^2=QS(OQ−OP)`
`=>(OP−OQ)(OP+OQ+QS)=0`
`thereforeOP=OQ`
Hence proved.
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