Prove that the circle drawn with any side of a rhombus as diameter, passes through the point of intersection of its diagonals

Explanation

To prove that the circle drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals, we will follow these steps:

### Step 1: Understand the properties of a rhombus
A rhombus is a quadrilateral where all sides are equal in length. The diagonals of a rhombus bisect each other at right angles (90 degrees).

### Step 2: Identify the points
Let the vertices of the rhombus be \( A, B, C, D \). The diagonals \( AC \) and \( BD \) intersect at point \( M \).

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