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In Figure, if /A O B=80^0a n d\ /A B C...

In Figure, if `/_A O B=80^0a n d\ /_A B C=30^0,` then find `/_C A O`

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` arc AB` subtends `/_AOB` at the centre
`/_ACB` at the remaining part of the circle
`/_ACB=1/2/_AOB=1/2xx80^0=40^0`
In `/_\ OAB ,OA=AB`
`/_OAB=/_OBA`
`/_OAB+/_OBA+/_AOB=180^0`
`/_OAB+/_OBA+80^0=180^0`
`/_OAB+/_OAB=180^0-80^0`
`/_OAB=100^0/2=50^0`
Similarly in `/_\ABC, /_BAC+/_ACB+/_ABC=180^0`
`/_BAC+40^0+30^0=180^0`
`/_BAC=180^0-70^0=110^0`
`/_CAO=/_BAC-/_OAB=110^0-50^0=60^0`
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