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In Figure, A is the centre of the circle...

In Figure, `A` is the centre of the circle. `A B C D` is a parallelogram and `C D E` is a straight line. Find `/_B C D\ :\ /_A B Edot`

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`ABCD||gm`
`/_A=/_`C
`/_C=/_ADE`(corresponding angles)
`/_BCD=/_ADE`
Also `/_ABE=BED`(alternate angles)
`arc BD` subtends `/_BAD` at the centre `BDE` at the remaining part of the circle.
`/_BED=1/2 /_A=1/2 /_C=1/2 /_ADE`,
`/_BCD//_ABE=/_BAD//_BED=(/_ADE)/(/_ADE)/2=2/1`
`/_BCD:/_ABE=2:1`
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