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If two diameters of a circle intersect...

If two diameters of a circle intersect each other at right angles, then quadrilateral formed by joining their end points is a rhombus        (b) rectangle   (c) parallelogram  (d) square
Let `AB \and\ CD` be the diagonals of a circle such that `AB_|_CD`

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Let `AB \and\ CD` be the diagonals of a circle such that `AB_|_CD`
Joining points `A,B,C,D` in order we see that `AB \and\ CD` are the equal diagonals of quad. `ACBD` which intersect at rightangle.
`ACBD` is a square.
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