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The average distance travelled by a mole...

The average distance travelled by a molecule of gas at temperature T between two successive collisions is called its mean free path which can be expressed by (P is pressure of gas, K is Boltzmann cosntant, d diameter of molecule)

A

`(1)/(sqrt(2)pid^(2)p)`

B

`(P)/(sqrt(2)pid^(2)T)`

C

`(KT)/(sqrt(2)pid^(2)P)`

D

`(KP)/(sqrt(2)pid^(2)T)`

Text Solution

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The correct Answer is:
C
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The constant motion and high velocities of gas particles lead to some important practical consquences. One such consquences is that gases mix rapidly when they come in contact. Take the stopper off a bottle of perfume, for instance, and the odour will spread rapidly through the room as perfume molecules mix with the molecules in the air. This mixing of different gases by random molecular motion and with frequent collision is called diffusion. A similar process in which gas molecules escape without collision through a tiny hole into a vacuum is called effusion. Both the processes follow Graham's law which is mathematically put as r prop sqrt(1//d) . The average distance travelled by molecules between successive collisions is called mean free path. Answer the following questions on the basis of the above information: When CO_(2) under high pressure is released from a fire extinguisher, particles of solid CO_(2) are formed, despite the low sublimation temperature (-77^(@)C) at 1 atm because

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