The volume of a gas is reduced adibatica...

The volume of a gas is reduced adibatically to `(1//4)` of its volume at `27^(@)C`. if `gamma = 1.4` . The new temperature will be

`350xx4^(0.4)K`

`300xx4^(0.4)K`

`150xx4^(0.4)K`

None of these

Text Solution

Verified by Experts

The correct Answer is:

Isothermal process `PdV+VdP=0`
`(dP)/(P)=-(dV)/(V), (K)=(dP)/(-((dV)/(V)))=(dP)/(((dP)/(P)))=P`

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