A steel ball of mass 0.1 kg falls freely...

A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel `=460 K//kg^(@)//C,g=10 m//s^(2)`)

`0.01 ^(@)C`

`0.1^(@)C`

`1^(@)C`

`1.1^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

`Deltah=h_(1)-h_(2), mg Deltah=mSDetaT`

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