The volume of 1 mol of a gas at standard temperature and pressure is .

Options

A. 11.2 litre
B. 22.4 litres
C. 100 litre
D. none of these

Explanation

To determine the volume of 1 mole of a gas at standard temperature and pressure (STP), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Conditions of STP**:
- Standard temperature is defined as 0 degrees Celsius, which is equivalent to 273.15 Kelvin.
- Standard pressure is defined as 1 atmosphere (atm).

2. **Use the Ideal Gas Law**:
- The ideal gas law states that \( PV = nRT \), where:
- \( P \) = pressure (in atm)
- \( V \) = volume (in liters)
- \( n \) = number of moles of gas
- \( R \) = ideal gas constant (0.0821 L·atm/(K·mol))
- \( T \) = temperature (in Kelvin)

3. **Substituting Values for 1 Mole of Gas**:
- We want to find the volume \( V \) when \( n = 1 \) mole, \( P = 1 \) atm, and \( T = 273.15 \) K.
- Plugging in the values into the ideal gas law:
\[ V = \frac{nRT}{P} \]
\[ V = \frac{(1 \text{ mol}) \times (0.0821 \text{ L·atm/(K·mol)}) \times (273.15 \text{ K})}{1 \text{ atm}} \]

4. **Calculating the Volume**:
- Now, calculate the volume:
\[ V = \frac{0.0821 \times 273.15}{1} \]
\[ V \approx 22.4 \text{ L} \]

5. **Conclusion**:
- Therefore, the volume of 1 mole of gas at standard temperature and pressure is approximately 22.4 liters.