`0.250g` of an element M, reacts with excess fluorine to produce `0.547g` of the hexafluoride `MF_(6)`. What is the elemejnt : `[Cr = 52, Mo = 96, S = 32, Te = 127.6]` .

Options

A. Cr
B. MO
C. S
D. Te

Answer

B

Explanation

`M + 6F rarr MF_(6)`
Mole of M = Mole of `MF_(6)`
`("wt")/("Mole wt") = ("wt")/("Mol wt")`
`(.25)/(x) = (.547)/(x + 19 xx 6)`
`28.5 + .25x = .547x`
`28.5 = .297 x rArr x = 95.959`
so element is `= Mo` .