In the compound `HC-=C-CH_(2)-CH=CH-CH_(3)`, the `C_(2)-C_(3)` bond is the type of :-

Options

A. `sp-sp^(2)`
B. `sp^(3)-sp^(3)`
C. `sp-sp^(3)`
D. `sp^(2)-sp^(2)`

Answer

To determine the type of bond between the second carbon (C2) and the third carbon (C3) in the compound `HC≡C-CH₂-CH=CH-CH₃`, we will analyze the structure step by step.

### Step-by-Step Solution:

1. **Identify the Structure**:
The given compound is `HC≡C-CH₂-CH=CH-CH₃`. This structure contains a triple bond between the first and second carbon atoms (C1 and C2) and a double bond between the fourth and fifth carbon atoms (C4 and C5).

2. **Number the Carbon Atoms**:
We will number the carbon atoms starting from the left side:
- C1: H (attached to a triple bond)
- C2: C (part of the triple bond)
- C3: CH₂ (single bond)
- C4: C (part of the double bond)
- C5: C (part of the double bond)
- C6: CH₃

3. **Determine the Type of Bond between C2 and C3**:
The bond between C2 and C3 is a single bond (C-C). Since C2 is part of a triple bond with C1 and C3 is connected to C2 with a single bond, we can conclude that the bond type between C2 and C3 is a single bond.

4. **Determine the Hybridization of C2 and C3**:
- **C2**: This carbon is involved in a triple bond, which means it is sp hybridized.
- **C3**: This carbon is connected to C2 with a single bond and has two other hydrogen atoms attached. Therefore, it is sp³ hybridized.

5. **Final Conclusion**:
The bond between C2 and C3 is a single bond, and the hybridization of C2 is sp, while the hybridization of C3 is sp³.

### Answer:
The bond between C2 and C3 is a **single bond** (C-C) with C2 being **sp hybridized** and C3 being **sp³ hybridized**.

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