The resistance of a `1N` solution of salt is `50 Omega`. Calculate the equivalent conductance of the solution, if the two platinum electrodes in solution are 2.1 cm apart and each having an area of `4.2 cm^(2)`.

Explanation

`k = (1)/(rho) = (1)/(R) ((l)/(A)) = (1)/(50) xx (2.1)/(4.2) = (1)/(100)` and `lambda_(eq) = (k xx 1000)/(N) = (1)/(100) xx (1000)/(1) = 10`