At infinite dilution the molar conductance of `AI^(+3)` and `SO_(4)^(-2)` ion are 189 and `160 Omega^(-1) cm^(2) "mole"^(-1)` resoectively. Calculate the equilvalent and molar conductivity at infinite dilute of `AI_(2)(SO_(4))_(3)`.

Explanation

`lambda_(eq.[AI_(2)(SO_(4))_(3)])^(prop) = (1)/(3) lambda_(AI^(+3))^(prop) +(1)/(2) lambda_(SO_(4)^(-2))^(prop)`
`= (1)/(3) xx 189 +(1)/(2) xx 160`
`= 143 Omega^(-1) cm^(2) eq^(-1)`
Molar conductivity `= lambda_(eq) xx V.F. = 143 xx 6`
`= 858 Omega^(-1) cm^(2) mol^(-1)`