A `100 cm^(3)` solution is prepared by dissolving 2g of `NaOH` in water. Calculate the normality of the solution.

Explanation

`2g NaOH = (2)/(40) g .eq = (1)/(20)g eq.`
`N = ((1)/(20))/(100) xx 1000 = (1)/(2) = 0.5N`