If `alpha = 50%` for `K_(4)[Fe(CN)_(6)]` then find Van't hoff factor 'i'

Explanation

To find the Van't Hoff factor 'i' for the compound \( K_4[Fe(CN)_6] \) given that \( \alpha = 50\% \), we can follow these steps:

### Step 1: Understand the given information
We know that:
- \( \alpha = 50\% = 0.5 \)
- The compound \( K_4[Fe(CN)_6] \) dissociates into ions.

### Step 2: Determine the dissociation of the compound
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