Hydrogen peroxide can be prepared by successive reaction:
`2NH_(4)HSO_(4) rarr H_(2)+(NH_(4))_(2)S_(2)O_(8)`
`(NH_(4))_(2)S_(2)O_(8)+2H_(2)O rarr 2NH_(4)HSO_(4)+H_(2)O_(2)`
The first reaction is an electrolytic reaction the second is steam distillation. what amount ofcurrent would have to be used in first reaction to produce enough intermediate to yield 100g pure `H_(2)O_(2)` per hour ? Assume `50%` anode current efficiency.

Answer

`315.36A`

Explanation

moles of `H_(2)O_(2) =` moles of `H_(2) = (100)/(34)`
wt. of `H_(2) = (100)/(17) = Z` it
`(100)/(17) = (1 xx1 xx 0.5 xx 3600)/(96500)`
`i = 315.36 Amp`.