Calculate the solubiltit and solubility product of `Co_(2) [Fe(CN)_(6)]` is water at `25^(@)C` from the following data: conductivity of a saturated solution of `Co_(2)[Fe(CN)_(6)]` is `2.06 xx 10^(-6) Omega^(-1) cm^(-1)` and that of water used `4.1 xx 10^(-7) Omega^(-1) cm^(-1)`. The ionic molar conductivites of `Co^(2+)` and `Fe(CN)_(6)^(4-)` are `86.0 Omega^(-1)cm^(-1) mol^(-1)` and `44.0 Omega^(-1) cm^(-1) mol^(-1)`.

Answer

`K_(sp) = 7.682 xx 10^(-7)`

Explanation

`lambda_(M) = (k xx 1000)/(M)`
`(86 xx 2+444) = ((2.06 xx 10^(-6) -4.1xx10^(-7))xx1000)/(s)`
`s = 2.678 xx 10^(-6)`
`K_(sp) = 4s^(3) = 7.687 xx 10^(-17)`