Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Explanation

For motion of particle `(mv^(2))/(r)=(Gmm)/((2r)^(2))`
`impliesv^(2)=(Gm)/(4r)impliesv=(1)/(2)sqrt((Gm)/(r))`