if the gravitaional force ware to vary inversely as `m^(th)` power of the distance then the time period of a planet in circular orbit of radius `r` aroung the sun will be proportional to

Options

A. `r^(3m//2)`
B. `r^(3m//2)`
C. `r^(m+1//2)`
D. `r^(m+1)//2`

Answer

D

Explanation

`Fprop(1)/(r^(m)),F=(C)/(r^(m))`
this force will provide the required centripetal force
therefore `momega^(2)r=(C)/(r^(m)),omega^(2)=(C)/(mr^(m+1))`
`T=(2pi)/(omega)impliesTpropr^((m+1)//2)`