A satellite is seen after every `8` hours over the equator at a place on the earth when its sense of rotation is opposite to the earth. The time interval after which it can be seen at the same place when the sense of rotation of earth and satellite is same will be:

Options

A. 8 hours
B. 12 hours
C. 24 hours
D. 6 hours

Answer

C

Explanation

Relative angular velocity when the particle are moving in same direction is
`omega_(1)+omega_(2)implies(omega_(1)+omega_(2))t=2pi`
`thereforeomega_(2)=(2pi)/(24)rad//sec,omega_(1)=(pi)/(6)`
When the particles are moving in the same direction then angular veloity becomes
`(omega_(1)-omega_(2))implies(omega_(1)-omega_(2))t=2pi`
By substituting `omega_(1)` and `omega_(2)` in equation we get `implies24hrs`