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Gravitational potential difference betwe...

Gravitational potential difference between surface of a planet and a point situated at a height of 20 m above its surface is 2joule/kg. if gravitational field is uniform, then the work done in taking a 5kg body of height 4 meter above surface will be-:

A

2J

B

20 J

C

40 J

D

10 J

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The correct Answer is:
To solve the problem, we need to find the work done in taking a 5 kg body to a height of 4 meters above the surface of a planet, given that the gravitational potential difference between the surface and a point 20 meters above is 2 joules/kg. ### Step-by-Step Solution: 1. **Identify the Gravitational Potential Difference:** The gravitational potential difference (ΔVg) between the surface of the planet and a point 20 meters above is given as: \[ \Delta V_g = 2 \, \text{J/kg} \] 2. **Calculate the Gravitational Field (Eg):** The gravitational potential difference is related to the gravitational field (Eg) by the formula: \[ \Delta V_g = -E_g \cdot d \] where \(d\) is the height difference (20 m in this case). Rearranging the formula gives: \[ E_g = -\frac{\Delta V_g}{d} \] Plugging in the values: \[ E_g = -\frac{2 \, \text{J/kg}}{20 \, \text{m}} = -0.1 \, \text{J/(kg·m)} = -\frac{1}{10} \, \text{J/(kg·m)} \] 3. **Determine the Work Done (W):** The work done in moving a mass \(m\) through a height \(h\) in a gravitational field is given by: \[ W = m \cdot \Delta V_g \] First, we need to find the gravitational potential difference for moving the 5 kg body to a height of 4 meters. The potential difference for this height can be calculated using: \[ \Delta V_g = -E_g \cdot h \] where \(h = 4 \, \text{m}\). Substituting the values: \[ \Delta V_g = -\left(-\frac{1}{10}\right) \cdot 4 = \frac{4}{10} = 0.4 \, \text{J/kg} \] 4. **Calculate the Total Work Done:** Now, substituting \(m = 5 \, \text{kg}\) and \(\Delta V_g = 0.4 \, \text{J/kg}\): \[ W = 5 \, \text{kg} \cdot 0.4 \, \text{J/kg} = 2 \, \text{J} \] ### Final Answer: The work done in taking the 5 kg body to a height of 4 meters above the surface of the planet is: \[ \boxed{2 \, \text{J}} \]

To solve the problem, we need to find the work done in taking a 5 kg body to a height of 4 meters above the surface of a planet, given that the gravitational potential difference between the surface and a point 20 meters above is 2 joules/kg. ### Step-by-Step Solution: 1. **Identify the Gravitational Potential Difference:** The gravitational potential difference (ΔVg) between the surface of the planet and a point 20 meters above is given as: \[ \Delta V_g = 2 \, \text{J/kg} ...
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ALLEN-GRAVITATION-Exercise 2 (Brain Teasers)
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  2. Gravitational potential difference between surface of a planet and a p...

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  3. Two concentric shells of masses M(1) and M(2) are having radii r(1) an...

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  4. In a certain region of space, the gravitational field is given by -(k)...

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  5. The potential energy of a body mass m is U=ax+by the magnitude of acce...

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  7. There is a concentric hole of radius R in a solid sphere of radius 2R....

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  8. If there were a smaller gravitational effect, which of the following f...

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  9. Select the correct alternative-

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  10. A particle of mass M is at a distance a from surface of a thin spheric...

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  11. Three particles are projected vertically upward from a point on the su...

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  12. When a satellite in a circular orbit around the earth enters the atmos...

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  13. A satellite is to be geo-stationary, which of the following are essent...

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  14. A cavity of radius R//2 is made inside a solid sphere of radius R. The...

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  15. A tunnel is dug along a chord of the earth at a perpendicular distance...

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  16. A double star is a system of two stars of masses m and 2m, rotating ab...

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  17. A solid sphere of uniform density and radius 4 units is located with i...

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  18. The magnitude of the gravitational field at distance r(1) and r(2) fro...

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  19. Mark the correct statement/s-:

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  20. Calculate the gravitational potential at the centre of base of a solid...

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