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The molar heat capacity of an ideal gas ...

The molar heat capacity of an ideal gas in a process varies as `C=C_(V)+alphaT^(2)` (where `C_(V)` is mola heat capacity at constant volume and `alpha` is a constant). Then the equation of the process is

A

`Ve^(-((alphaT^(2))/(2R)))=` Constant

B

`Ve^(-((alphaT^(2))/(R)))=` constant

C

`Ve^(-((2alphaT^(2))/(R)))=` constant

D

`Ve^(-((3alphaT^(2))/(2R)))=` constant

Text Solution

Verified by Experts

The correct Answer is:
A

Given
`C=C_(V)+alphaT^(2)`
`C_(V)+(RT)/(V)(dV)/(dT)=C_(V)+alphaT^(2)`
`int(alphaT)/(R)dT=int(dV)/(V)+lnk`
`(alphaT^(2))/(2R)=ln(kV)`
`kV=e^((alphaT^(2))/(2R))`
`thereforeVe^(-((alphaT^(2))/(2R)))`=constant
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